A) \[-1\]
B) 0
C) 1
D) \[\pi \]
Correct Answer: B
Solution :
\[I=\int_{0}^{\pi }{{{e}^{{{\sin }^{2}}x}}{{\cos }^{3}}x\,\,dx}\] \[\Rightarrow I=\int_{0}^{\pi }{{{e}^{{{\sin }^{2}}(\pi -x)}}{{\cos }^{3}}(\pi -x)\,}dx\] ?..(i) \[\Rightarrow I=-\int_{0}^{\pi }{{{e}^{{{\sin }^{2}}x}}{{\cos }^{3}}x\,dx}\] ?..(ii) Adding (i) and (ii), we get \[2I=0\] Þ \[I=0\].You need to login to perform this action.
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