A) \[(0,\,\,1)\]
B) (\[-1,\,\,0)\]
C) \[(1,\,\,e)\]
D) None of these
Correct Answer: C
Solution :
For \[0<x<1\], we have \[1<{{e}^{{{x}^{2}}}}<e\], so that \[\int_{0}^{1}{1dx<\int_{0}^{1}{{{e}^{{{x}^{2}}}}}dx<\int_{0}^{1}{e\,dx}\Rightarrow 1<\int_{0}^{1}{{{e}^{{{x}^{2}}}}dx<e.}}\]
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