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JEE Main & Advanced Mathematics Definite Integration Question Bank Properties of Definite Integration

  • question_answer
    The value of \[\int_{0}^{1}{(1+{{e}^{-{{x}^{2}}}})}\,dx=\]                              [IIT 1981]

    A)                 \[-1\]    

    B)                 2

    C)                 \[1+{{e}^{-1}}\]

    D)                 None of these

    Correct Answer: D

    Solution :

                    \[\int_{0}^{1}{dx+\int_{0}^{1}{{{e}^{-{{x}^{2}}}}dx=1+\int_{0}^{1}{{{e}^{-{{x}^{2}}}}dx}}}\], but \[\int_{0}^{1}{{{e}^{-{{x}^{2}}}}}dx\] is not integrable.


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