A) \[a\]
B) \[\frac{a}{2}\]
C) \[2a\]
D) 0
Correct Answer: A
Solution :
\[I=\int_{0}^{2a}{\frac{f(x)}{f(x)+f(2a-x)}dx}\] .....(i) \[I=\int_{0}^{2a}{\frac{f(2a-x)}{f(2a-x)+f(x)}\,}dx\] .....(ii) Adding (i) and (ii), we get \[2I=\int_{0}^{2a}{\,\,dx=2a\Rightarrow I=a}\].
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