A) 2
B) 4
C) 0
D) 8
Correct Answer: B
Solution :
Let \[x+1=t\] when \[x=-2\to 0\], then \[t=-1\to 1\] \[I=\int_{-1}^{1}{({{t}^{3}}+2+t\cos t)\ dt}\] \[\ \text{Since}\ \,{{t}^{3}}\text{and }t\ \text{cos}\,\,t\] are odd functions \[\therefore \]\[I=\int_{-1}^{1}{2dt=[2t]_{-1}^{1}=4}\].You need to login to perform this action.
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