A) 3
B) \[\frac{1}{3}\]
C) \[\frac{1}{\sqrt{3}}\]
D) \[\sqrt{3}\]
Correct Answer: A
Solution :
On differentiating both sides, we get \[-{{\sin }^{2}}x\ f(\sin x)\cos x=-\cos x\] Þ \[f(\sin x)=\frac{1}{{{\sin }^{2}}x}\]Þ \[f(x)=\frac{1}{{{x}^{2}}}\]Þ \[f\ \left( \frac{1}{\sqrt{3}} \right)=3\].You need to login to perform this action.
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