A) 0
B) 1
C) 2
D) 4
Correct Answer: D
Solution :
\[I=\int_{-2}^{2}{|x|dx}\]\[=-\int_{-2}^{0}{x\,dx+\int_{0}^{2}{x\,dx}}\]\[=-\left[ \frac{{{x}^{2}}}{2} \right]_{-2}^{0}+\left[ \frac{{{x}^{2}}}{2} \right]_{0}^{2}\] \[=-(-2)+(2)=4\].
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