A) Length = 50 cm, diameter = 0.5 mm
B) Length = 100 cm, diameter = 1 mm
C) Length = 200 cm, diameter = 2 mm
D) Length = 300 cm, diameter = 3 mm
Correct Answer: A
Solution :
\[Y=\frac{T/A}{\Delta l/l}\Delta l=\frac{T\times l}{A\times Y}=\frac{T}{Y}\times \frac{l}{A}\] Hence, \[\frac{T}{Y}\] is constant. Therefore, \[\Delta l=\frac{l}{A}\] \[\frac{l}{A}\] is largest in the first case.
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