A) An acid
B) An alcohol
C) An aldehyde
D) A nitrogen oxide
Correct Answer: C
Solution :
\[\underset{\text{Ethylamine}}{\mathop{C{{H}_{3}}-C{{H}_{2}}-N{{H}_{2}}}}\,\underset{[O]}{\mathop{\xrightarrow{KMn{{O}_{4}}}}}\,\underset{\text{Aldimine}}{\mathop{C{{H}_{3}}-CH=NH}}\,\] \[\xrightarrow{{{H}_{3}}{{O}^{+}}}\underset{\text{Acetaldehyde}}{\mathop{C{{H}_{3}}-CHO}}\,\]
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