A) Phenol
B) Aniline
C) Benzene
D) Nitro benzene
Correct Answer: B
Solution :
We know that \[\underset{\text{Aniline}}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,+\underset{\text{Chloroform}}{\mathop{CHC{{l}_{3}}}}\,+3KOH\to \underset{\text{phenyl isocyanide}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{{{C}_{6}}{{H}_{5}}NC+3KCl+3{{H}_{2}}O}}\,\] Thus in this reaction phenyl isocyanide is produced. this is called carbylamine reaction.
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