A) Ammonium acetate
B) Acetonitrile
C) \[N{{H}_{3}}\]
D) Methylamines
Correct Answer: B
Solution :
\[\underset{\text{Acetamide}}{\mathop{C{{H}_{3}}CON{{H}_{2}}}}\,\xrightarrow{{{P}_{2}}{{O}_{5}}}\underset{\text{Acetonitrile}}{\mathop{C{{H}_{3}}-C\equiv N}}\,\,+{{H}_{2}}O\].
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