A) \[C{{H}_{3}}CHO\]
B) \[C{{H}_{3}}CON{{H}_{2}}\]
C) \[C{{H}_{3}}COOH\]
D) \[C{{H}_{3}}C{{H}_{2}}NHOH\]
Correct Answer: C
Solution :
\[C{{H}_{3}}-C\equiv N\underset{\text{Reduction}}{\mathop{\xrightarrow{Na+EtOH}}}\,C{{H}_{3}}-C{{H}_{2}}-N{{H}_{2}}\] \[\xrightarrow{HN{{O}_{2}}}C{{H}_{3}}C{{H}_{2}}-OH\underset{{{H}_{2}}S{{O}_{4}}}{\mathop{\xrightarrow{{{K}_{2}}C{{r}_{2}}{{O}_{7}}}}}\,C{{H}_{3}}COOH\]
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