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10th Class Mathematics Quadratic Equations Question Bank Quadratic Equations

  • question_answer
    Roots of the quadratic equation \[{{x}^{2}}+x-(a+1)\,(a+2)=0\] are _____.

    A)  \[-(a+1),\,(a+2)\]

    B)                     \[(a+1),\,-(a+2)\]

    C)                     \[(a+1),(a+2)\]

    D)                     \[-(a+1),-(a+2)\]

    Correct Answer: B

    Solution :

    Given equation is             \[{{x}^{2}}+x-(a+1)(a+2)=0\] \[\Rightarrow \]\[{{x}^{2}}+(a+2)x-(a+1)x-(a+1)\,(a+2)=0\] \[\Rightarrow \]  \[x(x+(a+2))-(a+1)(x+(a+2))=0\] \[\Rightarrow \] \[(x-(a+1))\,(x+(a+2))=0\] \[\Rightarrow \]            \[x=(a+1)\] or \[x=-\,(a+2)\]


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