A) \[\frac{b(c-a)}{a(b-c)}\]
B) \[\frac{a(b-c)}{c(a-b)}\]
C) \[\frac{a(b-c)}{b(c-a)}\]
D) \[\frac{c(a-b)}{a(b-c)}\]
Correct Answer: D
Solution :
Given equation is \[a(b-c){{x}^{2}}+b(c-a)x+c(a-b)=0\] Let \[\alpha \] be the other root. then Product of roots \[=\alpha \times 1=\frac{c(a-b)}{a(b-c)}\] \[\Rightarrow \] \[\alpha =\frac{c}{a}\,\left( \frac{a-b}{b-c} \right)\]You need to login to perform this action.
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