A) Rectangle
B) Rhombus
C) Parallelogram
D) Square
Correct Answer: C
Solution :
In quadrilateral AXCY, \[AX||CY\] (\[\because \]\[AB||CD\]) ?(i) \[AX=\frac{1}{2}AB\]and \[CY=\frac{1}{2}CD\] (\[\therefore \]X and Y are midpoint of AB and CD) Also, AB = CD (Opposite sides of parallelogram) So, \[AX=CY\] \[\Rightarrow \]AXCY is a parallelogram (from (i) and (ii)) Similarly, quadrilateral DXBY is a parallelogram. In quadrilateral SXRY, \[SX||YR\] (\[\because \]SX is a part of DX and YR is a part of YB) Similarly, \[SY||XR\] So, SXRY is a parallelogram.You need to login to perform this action.
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