A) 5 kilometres West
B) 5 kilometres North-east
C) 7 kilometres East
D) 7 kilometres West
Correct Answer: B
Solution :
Explanation: The movements of Vijay are as shown in (A to B, B to C and C to D). \[AC=\left( AB-BC \right)=\left( 10-6 \right)\text{ }km=4\text{ }km\] Clearly, D is the North-east of A. Vijay distance from starting point \[A=AD=\sqrt{A{{C}^{2}}}+C{{D}^{2}}\] \[=\,\,\sqrt{{{4}^{2}}}+{{3}^{2}}=\sqrt{25}\,\,=\,\,5\,km\] So, Vijay is 5 km to the North-east of his starting point.You need to login to perform this action.
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