A) \[\frac{1}{6}\]
B) \[\frac{1}{8}\]
C) \[\frac{1}{9}\]
D) \[\frac{1}{12}\]
E) None of these
Correct Answer: C
Solution :
Explanation Option (c) is correct. In two throws of a die, n (S) = \[(6\times 6)=36\] Let E = event of getting a sum 9 = {(3, 6), (4, 5), (5, 4), (6, 3)} \[P(E)=\frac{n(E)}{n(S)}=\frac{4}{36}=\frac{1}{9}.\]
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