A) Two
B) One
C) Half
D) Zero
Correct Answer: C
Solution :
\[r=K{{[A]}^{m}}\] also \[2\,\text{r}=K{{[4A]}^{\,m}}\], \[\frac{1}{2}={{\left( \frac{1}{4} \right)}^{m}}\] \[\therefore \,\,m=\frac{1}{2}\]You need to login to perform this action.
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