JEE Main & Advanced Chemistry Chemical Kinetics Question Bank Rate of a reaction

  • question_answer A gaseous hypothetical chemical equation \[2A\]⇌\[4B+C\]is carried out in a closed vessel. The concentration of B is found to increase by \[5\times {{10}^{-3}}mol\,\,{{l}^{-1}}\] in 10 second. The rate of appearance of B is           [AFMC 2001]

    A)                 \[5\times {{10}^{-4}}mol\,\,{{l}^{-1}}se{{c}^{-1}}\]          

    B)                 \[5\times {{10}^{-5}}mol\,\,{{l}^{-1}}se{{c}^{-1}}\]

    C)                 \[6\times {{10}^{-5}}mol\,\,{{l}^{-1}}{{\sec }^{-1}}\]       

    D)                 \[4\times {{10}^{-4}}mol\,{{l}^{-1}}{{\sec }^{-1}}\]

    Correct Answer: A

    Solution :

               Increase in concentration of \[B=5\times {{10}^{-3}}mol\,\,{{l}^{-1}}\] \[Time=10\,\,\sec \]                    Rate of appearance of \[\text{B}=\]\[\frac{\text{Increase}\,\text{of}\,\text{conc}\text{. B}}{\text{Time}\,\,\text{taken}}\]                                 \[=\frac{5\times {{10}^{-3}}mol\,\,{{l}^{-1}}}{10\,\,\sec }=5\times {{10}^{-4}}mol\,\,{{l}^{-1}}\,\,Se{{c}^{-1}}\]


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