A) \[5\times {{10}^{-4}}mol\,\,{{l}^{-1}}se{{c}^{-1}}\]
B) \[5\times {{10}^{-5}}mol\,\,{{l}^{-1}}se{{c}^{-1}}\]
C) \[6\times {{10}^{-5}}mol\,\,{{l}^{-1}}{{\sec }^{-1}}\]
D) \[4\times {{10}^{-4}}mol\,{{l}^{-1}}{{\sec }^{-1}}\]
Correct Answer: A
Solution :
Increase in concentration of \[B=5\times {{10}^{-3}}mol\,\,{{l}^{-1}}\] \[Time=10\,\,\sec \] Rate of appearance of \[\text{B}=\]\[\frac{\text{Increase}\,\text{of}\,\text{conc}\text{. B}}{\text{Time}\,\,\text{taken}}\] \[=\frac{5\times {{10}^{-3}}mol\,\,{{l}^{-1}}}{10\,\,\sec }=5\times {{10}^{-4}}mol\,\,{{l}^{-1}}\,\,Se{{c}^{-1}}\]
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