• # question_answer The rate of a reaction is doubled for every ${{10}^{o}}$ rise in temperature. The increase in reaction rate as a result of temperature rise from ${{10}^{o}}$ to ${{100}^{o}}$ is [KCET 1993; Kerala PET 2002; MP PET 2003] A)                 112         B)                 512 C)                 400         D)                 614

Solution :

$\frac{{{k}_{t}}+10}{{{K}_{t}}}=\frac{{{r}_{t}}+10}{{{r}_{t}}}=2$                                 For an increase of temperature to ${{90}^{o}}C$ i.e. 9 times, the rate increases by ${{2}^{9}}$ times i.e. 512.

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