JEE Main & Advanced Chemistry Chemical Kinetics Question Bank Rate of a reaction

  • question_answer Velocity constant of a reaction at 290 K was found to be\[3.2\times {{10}^{-3}}\]. At 310 K it will be about              [KCET 1989, 91]

    A)                 \[1.28\times {{10}^{-2}}\]            

    B)                 \[9.6\times {{10}^{-3}}\]

    C)                 \[6.4\times {{10}^{-3}}\]              

    D)                 \[3.2\times {{10}^{-4}}\]

    Correct Answer: A

    Solution :

                    For 10K rise in temperature, the rate of reaction nearly doubles.

adversite


You need to login to perform this action.
You will be redirected in 3 sec spinner