JEE Main & Advanced Chemistry Chemical Kinetics Question Bank Rate of a reaction

  • question_answer For the reaction\[2{{N}_{2}}{{O}_{5(g)}}\to 4N{{O}_{2(g)}}+{{O}_{2(g)}}\], if concentration of \[N{{O}_{2}}\] in 100 seconds is increased by \[5.2\times {{10}^{-3}}m\]. Then rate of reaction will be [Kerala CET  2005]

    A)                 \[1.3\times {{10}^{-5}}m{{s}^{-1}}\]       

    B)                 \[5\times {{10}^{-4}}m{{s}^{-1}}\]

    C)                 \[7.6\times {{10}^{-4}}m{{s}^{-1}}\]       

    D)                 \[2\times {{10}^{-3}}m{{s}^{-1}}\]

    E)                 \[2.5\times {{10}^{-5}}m{{s}^{-1}}\]

    Correct Answer: A

    Solution :

               \[2{{N}_{2}}{{O}_{5(g)}}\to 4N{{O}_{2(g)}}+{{O}_{2(g)}}\]                    Rate of reaction with respect to \[N{{O}_{2}}\]                                 \[=\frac{1}{4}\frac{d[N{{O}_{2}}]}{dt}=\frac{1}{4}\times \frac{5.2\times {{10}^{-3}}}{100}=1.3\times {{10}^{-5}}m{{s}^{-1}}\]


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