A) \[1.3\times {{10}^{-5}}m{{s}^{-1}}\]
B) \[5\times {{10}^{-4}}m{{s}^{-1}}\]
C) \[7.6\times {{10}^{-4}}m{{s}^{-1}}\]
D) \[2\times {{10}^{-3}}m{{s}^{-1}}\]
E) \[2.5\times {{10}^{-5}}m{{s}^{-1}}\]
Correct Answer: A
Solution :
\[2{{N}_{2}}{{O}_{5(g)}}\to 4N{{O}_{2(g)}}+{{O}_{2(g)}}\] Rate of reaction with respect to \[N{{O}_{2}}\] \[=\frac{1}{4}\frac{d[N{{O}_{2}}]}{dt}=\frac{1}{4}\times \frac{5.2\times {{10}^{-3}}}{100}=1.3\times {{10}^{-5}}m{{s}^{-1}}\]
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