A) m : n
B) na : mb
C) a : b
D) md : nc
Correct Answer: C
Solution :
Let \[\frac{a}{b}=\frac{c}{d}\] - x (say) ...(i) \[\Rightarrow \]\[a=bx,c=dx\] ...(ii) Now, \[\frac{ma+nc}{mb+nd}=\frac{mbx+ndx}{mb+nd}\] [using (ii)] \[\Rightarrow \]\[\frac{ma+nc}{mb+nd}=\frac{(mb+nd)x}{mb+nd}=X\] \[\Rightarrow \]\[\frac{ma+nc}{mb+nd}=\frac{a}{b}\] [using (i)]
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