7th Class Mathematics Rational Numbers Question Bank Rational Numbers

  • question_answer
    Simplify: \[\frac{\left( -18\frac{1}{3}\times 2\frac{8}{11} \right)-\left( 4\frac{5}{7}\times 2\frac{1}{3} \right)}{\left| \frac{3}{5}+\left( \frac{-9}{10} \right) \right|+\left| \left( \frac{-3}{5} \right) \right|}\]

    A)  \[63\frac{4}{81}\]                 

    B)  \[-23\frac{7}{9}\]     

    C)         \[-67\frac{7}{9}\]

    D)         \[12\frac{6}{17}\]     

    Correct Answer: C

    Solution :

            We have, \[\frac{\left( -18\frac{1}{3}\times 2\frac{8}{11} \right)-\left( 4\frac{5}{7}\times 2\frac{1}{3} \right)}{\left| \frac{3}{5}+\left( \frac{-9}{10} \right) \right|+\left| -\left( \frac{-3}{5} \right) \right|}\] \[=\frac{\left( \frac{-55}{3}\times \frac{30}{11} \right)-\left( \frac{33}{7}\times \frac{7}{3} \right)}{\left| \frac{3}{5}-\frac{9}{10} \right|+\left| \frac{3}{5} \right|}=\frac{-50-11}{\left| \frac{6-9}{10} \right|+\frac{3}{5}}\] \[=\frac{-61}{\frac{3}{10}+\frac{3}{5}}=\frac{-61}{\frac{3+6}{10}}\] \[=\frac{-61\times 10}{9}=\frac{-610}{9}=-67\frac{7}{9}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner