A) \[\frac{1}{4},\frac{6}{4},\frac{16}{9},\frac{25}{4}\]
B) \[\frac{-3}{6},\frac{-4}{3},\frac{-9}{4},\frac{-13}{4}\]
C) \[\frac{-5}{8},\frac{-3}{8},\frac{0}{8},\frac{1}{8}\]
D) \[\frac{-7}{4},\frac{-3}{4},\frac{5}{4},\frac{8}{3}\]
Correct Answer: B
Solution :
\[\frac{-3}{6},\frac{-4}{3},\frac{-9}{4},\frac{-13}{4}\] First we need to make the denominator same by taking L.C.M (6, 3, 4, 4) = 12 Now, \[\frac{-3}{6}=\frac{-3\times 2}{6\times 2}=\frac{-6}{12};\,\frac{-4}{3}=\frac{-4\times 4}{3\times 4}=\frac{-16}{12};\] \[\frac{-9}{4}=\frac{-9\times 3}{4\times 3}=\frac{-27}{12};\,\frac{-13}{4}=\frac{-13\times 3}{4\times 3}=\frac{-39}{12}\] Since, \[-6\,>-16\,>\,-27\,>\,-\,39\] \[\therefore \] \[\frac{-3}{6},\frac{-4}{3},\frac{-9}{4},\frac{-13}{4}\] are in descending order.
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