A) \[\frac{-8}{37}\]
B) \[\frac{-5}{12}\]
C) \[\frac{6}{31}\]
D) \[\frac{3}{12}\]
Correct Answer: B
Solution :
Sum of \[\frac{5}{12}\] and \[\frac{-17}{24}\] is \[\frac{5}{12}+\left( \frac{-17}{24} \right)=\frac{5}{12}-\frac{17}{24}=\frac{10-17}{24}=\frac{-7}{24}\] Product of \[\frac{2}{5}\] and \[\frac{7}{4}\] is \[\frac{2}{5}\times \frac{7}{4}=\frac{7}{10}\] According to the question, we have \[\frac{-7}{24}\div \frac{7}{10}=\frac{-7}{24}\times \frac{10}{7}=\frac{-5}{12}\]
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