A) \[\frac{23}{30}\]
B) \[\frac{23}{36}\]
C) \[\frac{18}{49}\]
D) \[\frac{17}{25}\]
Correct Answer: A
Solution :
(a): Let the total number of student in class VIII be x \[\therefore \] Number of girls \[\frac{3}{5}x\] and number of Boys \[=x-\frac{3x}{5}=\frac{2x}{5}\] Number of girls who are absent \[=\frac{3}{5}\times \frac{2}{9}x=\frac{6x}{45}\] And number of boys who are absent \[=\frac{2}{5}\times \frac{1}{4}x=\frac{x}{10}\] \[\therefore \] Total number of students who are presents \[=x-\frac{6x}{45}-\frac{x}{10}\] \[=\frac{90x-12x-9x}{90}=\frac{69x}{90}\] \[\therefore \] the \[\frac{23}{30}\] part of the student are present in Class VIIIYou need to login to perform this action.
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