A) \[\frac{2}{99}\]
B) \[\frac{1}{50}\]
C) \[\frac{1}{100}\]
D) \[\frac{3}{200}\]
Correct Answer: C
Solution :
(c): \[\frac{2}{3}\times \frac{3}{4}\times \frac{4}{5}\times .........\times \frac{98}{99}\times \frac{99}{100}\times .....\frac{198}{199}\times \frac{199}{200}\] \[=\frac{2}{200}=\frac{1}{100}\]
You need to login to perform this action.
You will be redirected in
3 sec
