A) 0
B) \[{{10}^{80}}\]
C) \[{{10}^{20}}\]
D) None of these
Correct Answer: D
Solution :
(d): \[{{\left( {{a}^{m}} \right)}^{n}}={{a}^{mn}}\therefore {{(10)}^{2}}=100\Rightarrow {{10}^{{{(10)}^{2}}}}={{10}^{100}}\] \[{{\left( {{10}^{10}} \right)}^{2}}={{10}^{10\times 2}}={{10}^{20}}\] \[\therefore \] Difference \[1-{{10}^{20}}={{10}^{20}}\left( {{10}^{80}}-1 \right)\]: so it is of the order of \[{{10}^{100}}\]You need to login to perform this action.
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