10th Class Mathematics Real Numbers Question Bank Real Numbers

  • question_answer
    A positive integer n when divided by 9, gives 7 as remainder. What will be the remainder when \[(3n-1)\] is divided by 9?

    A) 1                     

    B)        2                     

    C)  3                    

    D)         4                    

    Correct Answer: B

    Solution :

    We have, \[n=9q+7,\]where q is the quotient. \[\Rightarrow \]            \[3n=27q+21\]   (Multiply by 3) \[\Rightarrow \]            \[3n-1=27q+20=9(3q+2)+2\] So, remainder is 2, when \[(3n-1)\] is divided by 9.

You need to login to perform this action.
You will be redirected in 3 sec spinner