• # question_answer A positive integer n when divided by 9, gives 7 as remainder. What will be the remainder when $(3n-1)$ is divided by 9? A) 1                      B)        2                      C)  3                     D)         4

We have, $n=9q+7,$where q is the quotient. $\Rightarrow$            $3n=27q+21$   (Multiply by 3) $\Rightarrow$            $3n-1=27q+20=9(3q+2)+2$ So, remainder is 2, when $(3n-1)$ is divided by 9.