Correct Answer: B
Solution :We have, \[n=9q+7,\]where q is the quotient. \[\Rightarrow \] \[3n=27q+21\] (Multiply by 3) \[\Rightarrow \] \[3n-1=27q+20=9(3q+2)+2\] So, remainder is 2, when \[(3n-1)\] is divided by 9.
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