JEE Main & Advanced Physics Ray Optics Question Bank Refraction at Curved Surface

  • question_answer
    A point object is placed at the center of a glass sphere of radius 6 cm and refractive index 1.5. The distance of the virtual image from the surface of the sphere is  [IIT-JEE (Screening) 2004]

    A)            2 cm                                         

    B)            4 cm

    C)            6 cm                                         

    D)            12 cm

    Correct Answer: C

    Solution :

                       Using refraction formula  \[\frac{_{1}{{\mu }_{2}}-1}{R}=\frac{_{1}{{\mu }_{2}}}{v}-\frac{1}{u}\]                    in given case, medium (1) is glass and (2) is air                    So \[\frac{_{g}{{\mu }_{a}}-1}{R}=\frac{_{g}{{\mu }_{a}}}{v}-\frac{1}{u}\] \[\Rightarrow \frac{\frac{1}{1.5}-1}{-6}=\frac{1}{1.5\,v}-\frac{1}{-6}\]                    \[\Rightarrow \frac{1-1.5}{-6}=\frac{1}{v}+\frac{1.5}{6}\]\[\Rightarrow \frac{0.5}{6}=\frac{1}{v}+\frac{1}{4}\]            \[\Rightarrow \frac{1}{v}=\frac{1}{12}-\frac{1}{4}=-\frac{2}{12}=-\frac{1}{6}\]Þ v = 6 cm


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