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JEE Main & Advanced Physics Ray Optics Question Bank Refraction at Curved Surface

  • question_answer
    A double convex lens \[({{R}_{1}}={{R}_{2}}=10\,cm)\]\[(\mu =1.5)\] having focal length equal to the focal length of a concave mirror. The radius of curvature of the concave mirror is  [Orssia PMT 2004]

    A)            10 cm                                      

    B)            20 cm

    C)            40 cm                                      

    D)            15 cm

    Correct Answer: B

    Solution :

                       \[\frac{1}{f}=\,(\mu -1)\,\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\] = \[(1.5-1)\,\left( \frac{1}{10}+\frac{1}{10} \right)=\frac{1}{10}\] Þ f = 10 cm \ Radius of curvature of concave mirror = 2f = 20 cm.


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