A) Decrease and change sign
B) Increase and change sign
C) Decrease and remain of the same sign
D) Increase and remain of the same sign
Correct Answer: B
Solution :
\[\frac{{{f}_{l}}}{{{f}_{a}}}=\frac{_{a}{{\mu }_{g}}-1}{_{l}{{\mu }_{g}}-1}=\frac{(1.5-1)\times 1.7}{(1.5-1.7)}\] \[\Rightarrow {{f}_{l}}=\frac{0.85}{-0.2}\]\[{{f}_{a}}=-\,4.25\,{{f}_{a}}\].
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