JEE Main & Advanced Physics Ray Optics Question Bank Refraction at Curved Surface

  • question_answer
    A thin equiconvex lens is made of glass of refractive index 1.5 and its focal length is 0.2 m, if it acts as a concave lens of 0.5 m focal length when dipped in a liquid, the refractive index of the liquid is                                            [EAMCET 2005]

    A)            \[\frac{17}{8}\]                   

    B)            \[\frac{15}{8}\]                                                                      

    C)            \[\frac{13}{8}\]                   

    D)            \[\frac{9}{8}\]

    Correct Answer: B

    Solution :

                       \[\frac{{{f}_{l}}}{{{f}_{a}}}=\frac{_{a}{{\mu }_{g}}-1}{_{l}{{\mu }_{g}}-1}\] Þ \[\frac{-0.5}{0.2}=\frac{1.5-1}{_{l}{{\mu }_{g}}-1}\] Þ \[_{l}{{\mu }_{g}}-1=-0.2\]                    Þ \[_{l}{{\mu }_{g}}=0.8=\frac{4}{5}\] Þ \[\frac{_{a}{{\mu }_{g}}}{_{a}{{\mu }_{l}}}=\frac{4}{5}\] Þ \[\frac{1.5}{_{a}{{\mu }_{l}}}=\frac{4}{5}\]            Þ \[_{a}{{\mu }_{l}}=\frac{15}{8}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner