A) 15 cm, concave
B) 15 cm, convex
C) \[\infty \], neither concave nor convex
D) 0, concave
Correct Answer: A
Solution :
\[\frac{1}{f}=\left( _{g}{{\mu }_{a}}-1 \right)\,\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)=\left( \frac{2}{3}-1 \right)\,\left( \frac{2}{10} \right)\] \[\Rightarrow \]\[f=-15\,cm\], so behaves as concave lens.
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