JEE Main & Advanced Physics Ray Optics Question Bank Refraction at Curved Surface

  • question_answer
    A convex lens of focal length 40 cm is in contact with a concave lens of focal length 25 cm. The power of combination is   [IIT-JEE 1982; AFMC 1997; CBSE PMT 2000; RPMT 2003]

    A) - 1.5 D                                    

    B) - 6.5 D

    C) + 6.5 D                                    

    D) + 6.67 D

    Correct Answer: A

    Solution :

    Focal length of the combination can be calculated as                    \[\frac{1}{F}=\frac{1}{{{f}_{1}}}+\frac{1}{{{f}_{2}}}\]\[\Rightarrow \frac{1}{F}=\frac{1}{(+40)}+\frac{1}{(-25)}\] \[\Rightarrow F=-\frac{200}{3}cm\]            \[\therefore P=\frac{100}{F}=\frac{100}{-200/3}=-1.5\ D\]


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