A) R
B) 2R
C) 4R
D) R / 2
Correct Answer: C
Solution :
\[\frac{{{f}_{l}}}{{{f}_{a}}}=\frac{_{a}{{\mu }_{g}}-1}{_{l}{{\mu }_{g}}-1}\] Þ \[{{f}_{l}}=4R\]
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