A) \[nf\]
B) \[\frac{f}{n}\]
C) \[(n+1)\,f\]
D) \[(n-1)\,f\]
Correct Answer: C
Solution :
\[m=\frac{f}{(f+u)}\Rightarrow -\frac{1}{n}=\frac{f}{(f+u)}\]\[\Rightarrow u=-\ (n+1)f\]
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