JEE Main & Advanced Physics Ray Optics Question Bank Refraction at Curved Surface

  • question_answer
    A lens which has focal length of 4 cm and refractive index of 1.4 is immersed in a liquid of refractive index 1.6, then the focal length will be [RPMT 1999]                             

    A) - 12.8 cm                               

    B) 32 cm

    C) 12.8 cm                                   

    D) - 32 cm

    Correct Answer: A

    Solution :

    \[\frac{{{f}_{l}}}{{{f}_{a}}}=\left( \frac{_{a}{{\mu }_{g}}-1}{_{l}{{\mu }_{g}}-1} \right)\Rightarrow \frac{{{f}_{l}}}{4}=\frac{(1.4-1)}{\frac{1.4}{1.6}-1}\Rightarrow {{f}_{l}}=-12.8\,cm\]


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