question_answer

On a glass plate a light wave is incident at an angle of \[60{}^\circ \]. If the reflected and the refracted waves are mutually perpendicular, the refractive index of material is [MP PMT 1994; Haryana CEE 1996;  KCET 1994; 2000]

A) \[\frac{\sqrt{3}}{2}\]        

B) \[\sqrt{3}\]

C) \[\frac{3}{2}\]                      

D) \[\frac{1}{\sqrt{3}}\]

Correct Answer: B

Solution :

From figure              \[<i={{60}^{o}},\]\[<r={{30}^{o}}\]            so \[\mu =\frac{\sin 60}{\sin 30}=\sqrt{3}\]