A) \[2.67\times {{10}^{8}}\] m/s
B) \[2.25\times {{10}^{8}}\] m/s
C) \[1.78\times {{10}^{8}}\] m/s
D) \[1.50\times {{10}^{8}}\] m/s
Correct Answer: B
Solution :
\[\mu \propto \frac{1}{v}\Rightarrow \frac{{{\mu }_{g}}}{{{\mu }_{w}}}=\frac{{{v}_{w}}}{{{v}_{g}}}\Rightarrow \frac{3/2}{4/3}=\frac{{{v}_{w}}}{2\times {{10}^{8}}}\] \[\Rightarrow {{v}_{w}}=2.25\times {{10}^{8}}m/s\]
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