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JEE Main & Advanced Physics Ray Optics Question Bank Refraction of Light at Plane Surfaces

  • question_answer
    The distance travelled by light in glass (refractive index =1.5)  in a nanosecond will be                     [MP PET 1999]

    A)            45 cm                                      

    B)            40 cm

    C)            30 cm                                      

    D)            20 cm

    Correct Answer: D

    Solution :

                       Distance =\[v\times t=\frac{c}{\mu }\times t=\frac{3\times {{10}^{8}}}{1.5}\times {{10}^{-9}}\]            = 0.2 m = 20 cm.


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