Railways NTPC (Technical Ability) Refrigeration and Air-Conditioning Question Bank Refrigeration and Air-Conditioning

  • question_answer
    The operating temperature of a cold storage is \[-2{}^\circ C,\] Heat leakage form the surrounding is 30 kW for the ambient temperature of \[40{}^\circ C.\] the actual COP of the refrigeration plant used is one fourth that of an ideal plant working between the same temperatures. The power required to drive the plant is:

    A) 1.86 kW           

    B) 3.72 kW

    C) 7.44 kW           

    D) 18.60 kW

    Correct Answer: D

    Solution :

    \[{{(COP)}_{th}}=\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}=\frac{271}{313-271}=6.4524\] \[{{(COP)}_{act}}=\frac{6.4524}{4}=1.613\] Worked required \[\frac{Q}{{{(COP)}_{act}}}=\frac{30}{1.613}=18.60\,\,kW\]


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