• # question_answer A heat pump working on a reversed carnot cycle has a COP of 5. If it works as a refrigerator taking 1 kW work input, the refrigerating effect will be: A) 1 kW                B) 2 kWC) 3 kW                D) 4 kW

COP of heat pump $=\frac{{{Q}_{s}}}{W}=5$ ${{Q}_{r}}=5W$ ${{Q}_{s}}=R+W$ $5W-W=R$ $R=4W=4\times 1=4\,k\,W$