• # question_answer The power (kW) required per ton of refrigeration is $\frac{N}{COP,}$ where COP is the coefficient of performance then N is equal to: A) 2.75                             B) 3.50C) 4.75                             D) 5.25

$COP\,\,=\,\,\frac{Q}{COP}\,\,=\,\,\frac{1TR}{W}$ $W\,\,=\,\,\frac{1TR}{W}\frac{N}{COP}$ $\therefore \,\,N\,\,=\,\,1TR\,\,=\,\,350$