A) 50% and 0.00622
B) 100% and 0.0126
C) 50% and 0.0126
D) 100% and 0.00622
Correct Answer: A
Solution :
\[{{P}_{a}}\,\,=\,\,1.01\] bar, \[{{P}_{v}}\,\,=\,\,0.01\] bar, \[{{P}_{s}}=0.02\] bar \[RH=\frac{{{P}_{v}}}{{{P}_{s}}}=\frac{0.01}{0.02}\]Or 50% \[W=\frac{0.622{{p}_{V}}}{{{P}_{a\,}}-{{P}_{v}}}=\frac{0.622\times 0.01}{1.01-0.01}=0.00622\]
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