2. Questions Bank
  3. Railways
  4. NTPC (Technical Ability)
  5. Refrigeration and Air-Conditioning

Railways NTPC (Technical Ability) Refrigeration and Air-Conditioning Question Bank Refrigeration and Air-Conditioning

  • question_answer
    When \[40{}^\circ C\] and \[25{}^\circ C\] are the dry bulb temperatures of air entering and leaving a cooling coil, then the cooling coil temperature is \[20{}^\circ C.\]What is the bypass factor for the case of sensible cooling?

    A) 0.20                             

    B) 0.25

    C) 0.50                             

    D) 0.60

    Correct Answer: B

    Solution :

    \[{{t}_{d1}}=40\,d{}^\circ C,\] \[{{t}_{d2}}=25{}^\circ C,\] \[{{t}_{d3}}=20{}^\circ C,\] \[BPF=\frac{{{t}_{d2}}-{{t}_{d3}}}{{{t}_{d1}}-{{t}_{d3}}}=\frac{25-20}{40-20}=\frac{5}{20}=0.25\]


You need to login to perform this action.
You will be redirected in 3 sec spinner