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Railways NTPC (Technical Ability) Refrigeration and Air-Conditioning Question Bank Refrigeration and Air-Conditioning

  • question_answer
    In an ideal refrigeration (reversed Carnot) cycle, the condenser and evaporator temperatures are \[27{}^\circ C\] and \[-13{}^\circ C\] respectively. The COP of this cycle would be'

    A) 6.5                               

    B) 7.5

    C) 10.5                             

    D) 15.0

    Correct Answer: A

    Solution :

    \[COP=\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}=\frac{260}{300-260}=\frac{260}{40}=6.5\]


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