• # question_answer In an ideal refrigeration (reversed Carnot) cycle, the condenser and evaporator temperatures are $27{}^\circ C$ and $-13{}^\circ C$ respectively. The COP of this cycle would be' A) 6.5                               B) 7.5C) 10.5                             D) 15.0

$COP=\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}=\frac{260}{300-260}=\frac{260}{40}=6.5$