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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Second Law of Motion

  • question_answer
    If a bullet of mass 5 gm moving with velocity 100 m /sec, penetrates the wooden block upto 6 cm. Then the average force imposed by the bullet on the block is       [MP PMT 2003]

    A)                         8300 N            

    B)                           417 N            

    C)                         830 N             

    D)                         Zero

    Correct Answer: B

    Solution :

                                \[u=100\ m/s,\ v=0,\ s=0.06\ m\] Retardation \[=a=\frac{{{u}^{2}}}{2s}=\frac{{{(100)}^{2}}}{2\times 0.06}=\frac{1\times {{10}^{6}}}{12}\] \[\therefore \] Force \[=ma=\frac{5\times {{10}^{-3}}\times 1\times {{10}^{6}}}{12}=\frac{5000}{12}=417\ N\]                        


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